BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
Sathish_jammy
Lapis Lazuli | Level 10

Dear Experts,

 

I need a patient count for the condition based on the cancer occurrence. I'll share the sample dataset and the expected result for your reference.

data have;
input ID Date mmddyy10. Inf Cancer;
cards;
123 05/05/2000 1 0
123 08/07/2001 0 1
123 06/07/2002 1 0
159 01/03/2001 1 1
159 02/08/2002 0 1
618 07/07/2005 0 0
618 05/03/2006 1 0
789 06/06/2000 1 0
789 04/02/2001 0 1
789 03/03/2002 1 0
789 03/03/2002 0 0
run;

 

I required 2 different outputs based on 2 conditions to get the patient IDs.

  1. Patients who are Infected(Inf=1) after/same date on cancer (cancer=1) Expected Output(IDs 123,159,789).
  2. Patients who are Infected(Inf=1) before cancer (cancer=1) Expected Output(IDs 123,789).

Kindly suggests a code to get the patient IDs list at the end of the result. 

Note: The first occurrence of Cancer is matters but not the following occurrence.

1 ACCEPTED SOLUTION

Accepted Solutions
Kurt_Bremser
Super User

This code gets your intended result, see if it also fits more complicated input data:

data have;
input ID Date mmddyy10. Inf Cancer;
format date MMDDYY10.;
cards;
123 05/05/2000 1 0
123 08/07/2001 0 1
123 06/07/2002 1 0
159 01/03/2001 1 1
159 02/08/2002 0 1
618 07/07/2005 0 0
618 05/03/2006 1 0
789 06/06/2000 1 0
789 04/02/2001 0 1
789 03/03/2002 1 0
789 03/03/2002 0 0
;

proc sql;
create table after as
select distinct a.id
from
  have (where=(inf = 1)) a,
  (select id, min(date) as date from have (where=(cancer = 1)) group by id) b
where a.id = b.id and a.date >= b.date;
create table before as
select distinct a.id
from
  have (where=(inf = 1)) a,
  (select id, min(date) as date from have (where=(cancer = 1)) group by id) b
where a.id = b.id and a.date < b.date;
quit;

View solution in original post

4 REPLIES 4
Kurt_Bremser
Super User

This code gets your intended result, see if it also fits more complicated input data:

data have;
input ID Date mmddyy10. Inf Cancer;
format date MMDDYY10.;
cards;
123 05/05/2000 1 0
123 08/07/2001 0 1
123 06/07/2002 1 0
159 01/03/2001 1 1
159 02/08/2002 0 1
618 07/07/2005 0 0
618 05/03/2006 1 0
789 06/06/2000 1 0
789 04/02/2001 0 1
789 03/03/2002 1 0
789 03/03/2002 0 0
;

proc sql;
create table after as
select distinct a.id
from
  have (where=(inf = 1)) a,
  (select id, min(date) as date from have (where=(cancer = 1)) group by id) b
where a.id = b.id and a.date >= b.date;
create table before as
select distinct a.id
from
  have (where=(inf = 1)) a,
  (select id, min(date) as date from have (where=(cancer = 1)) group by id) b
where a.id = b.id and a.date < b.date;
quit;
novinosrin
Tourmaline | Level 20

data have;
input ID Date mmddyy10. Inf Cancer;
format date mmddyy10.;
cards;
123 05/05/2000 1 0
123 08/07/2001 0 1
123 06/07/2002 1 0
159 01/03/2001 1 1
159 02/08/2002 0 1
618 07/07/2005 0 0
618 05/03/2006 1 0
789 06/06/2000 1 0
789 04/02/2001 0 1
789 03/03/2002 1 0
789 03/03/2002 0 0
;
proc sql;
/*Report 1 On/After*/
create table report1 as
select *
from have
group by id
having max(cancer=1);
/*Report 2 Before*/
create table report2 as
select *
from have
group by id
having min(ifn(inf=1,date,.)) < min(ifn(cancer=1,date,.)) ;
quit;
novinosrin
Tourmaline | Level 20

Since it appears your data is sorted by ID Date, Datastep seems a lot easier IMHO

 

data have;
input ID Date mmddyy10. Inf Cancer;
format date mmddyy10.;
cards;
123 05/05/2000 1 0
123 08/07/2001 0 1
123 06/07/2002 1 0
159 01/03/2001 1 1
159 02/08/2002 0 1
618 07/07/2005 0 0
618 05/03/2006 1 0
789 06/06/2000 1 0
789 04/02/2001 0 1
789 03/03/2002 1 0
789 03/03/2002 0 0
;
data report1 report2;
 do _n_=1 by 1 until(last.id);
  set have;
  by id;
  if nmiss(_d,_d1)=0 then continue;
  if not _d1 and  Cancer=1 then _d1=date;
  if not _d and inf=1 then _d=date;
 end;
 do _n_=1 to _n_;
  set have;
  if _d1 then output report1;
  if _d<_d1 then output report2;
 end;
 drop _:;
run;
Sathish_jammy
Lapis Lazuli | Level 10

Thank you for always stepping in to help when I need you most. @novinosrin @Kurt_Bremser it really meant a lot.

Ready to join fellow brilliant minds for the SAS Hackathon?

Build your skills. Make connections. Enjoy creative freedom. Maybe change the world. Registration is now open through August 30th. Visit the SAS Hackathon homepage.

Register today!
How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 4 replies
  • 559 views
  • 2 likes
  • 3 in conversation