Hello,
I am a beginner when it comes to SAS and this is my first project using SAS. I want to make sure that my interpretation of the odd ratio is accurate. I attached the output of my analysis and I also captured the effects table.
Response variable = "Age appropriate sleep duration" is the Response variable and it is binary i.e Child sleeps recommended age appropriate hours or Child did not sleep age appropriate recommended hours
Predictors :
1) ADHD Severity with two levels:
a Mild
b Moderate/Severe
Analysis was stratified based on ADHD Severity
2) Read to with 3 levels
a) 0-3 days
b) 4-6 days
c) Every day.
Analysis of Maximum Likelihood Estimates |
Parameter | | HrsSleep_1617 | Estimate | Standard
Error | t Value | Pr > |t| |
Intercept | | Child sleeps recommended age-appropriate hours | 0.3499 | 0.4741 | 0.74 | 0.4687 |
readto_1617 | 0 -3 days | Child sleeps recommended age-appropriate hours | -1.1681 | 0.6242 | -1.87 | 0.0753 |
readto_1617 | 4-6 days | Child sleeps recommended age-appropriate hours | -1.1306 | 0.8286 | -1.36 | 0.1869 |
NOTE: The degrees of freedom for the t tests is 21. |
Odds Ratio Estimates |
Effect | HrsSleep_1617 | Point Estimate | 95% Confidence Limits |
readto_1617 0 -3 days vs Every day | Child sleeps recommended age-appropriate hours | 0.311 | 0.085 | 1.139 |
readto_1617 4-6 days vs Every day | Child sleeps recommended age-appropriate hours | 0.323 | 0.058 | 1.809 |
NOTE: The degrees of freedom in computing the confidence limits is 21. |
Interpretation:
In children diagnosed with mild ADHD the odds of child sleeps recommended age appropriate hours in children read to 0-3 days is 0.689 less compared to children read to everyday.
Is this interpretation accurate? Thank you for the anticipated response.
