Current version: 9.04.01M5P091317
I need to find the non-consecutive integer ranges for a single column variable.
data have;
infile datalines missover;
input batchno;
datalines;
375
376
377
388
980
981
982
983
2008
2009
2010
;
run;
The output should provide beginning and ending values within each consecutive range.
That is, the output is a list of the following values for the input dataset shown above:
375
388
980
983
2008
2010
Thank you in advance for assistance.
Jane
/*Going with my assumption 378 is what to be in place instead of 388*/
data have;
infile datalines missover;
input batchno;
datalines;
375
376
377
378
980
981
982
983
2008
2009
2010
;
run;
data temp;
set have;
k=dif(batchno);
if k ne 1 then grp+1;
drop k;
run;
data want;
set temp;
by grp;
if first.grp or last.grp;
drop grp;
run;
HI @jawhitmire
375
388 /*is this correct or should it be 378?*/
My apologies if i am asking a dumb question plz
/*Going with my assumption 378 is what to be in place instead of 388*/
data have;
infile datalines missover;
input batchno;
datalines;
375
376
377
378
980
981
982
983
2008
2009
2010
;
run;
data temp;
set have;
k=dif(batchno);
if k ne 1 then grp+1;
drop k;
run;
data want;
set temp;
by grp;
if first.grp or last.grp;
drop grp;
run;
You need
data have;
infile datalines missover;
input batchno;
datalines;
375
376
377
388
980
981
982
983
2008
2009
2010
run;
data want (keep=start end);
merge have have (firstobs=2 keep=batchno rename=(batchno=nxt_batchno));
if batchno-1^=lag(batchno) then start=batchno;
retain start;
if batchno+1^=nxt_batchno;
end=batchno;
run;
Comparing the current to the prior (lag(batchno)) is relatively intuitive.
Comparing to the next can't rely on the lag function, so you need a way to read in 2 records at a time: the current record and the following record. Since they have the same variable, you have to rename one of them. Then do the comparison ("if batchno+1 ^= nxt_batchno;").
This worked perfectly and the output is clean. It seems my questions are slowly becoming a bit more difficult. I look forward to the day when I can contribute as much as I ask.
Thank you!
Jane
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