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jonatan_velarde
Lapis Lazuli | Level 10

Hi there:

 

i have this data

 

data have;

lenght animals$ 50;

input location animals$;

cards;

1 dog, cat, bird

2 cat

3 bird, dog

4 hamster

;

 

with this information, I need to keep the same column, but increase columns for each animal observed in the animal column:

 

LOCATION ANIMALS DOG CAT BIRD HAMSTER
1 dog, cat, bird 1 1 1 0
2 cat 0 1 0 0
3 bird, dog 1 0 1 0
4 hamster 0 0 0 1

       

Where 1means YES and 0 meams NO.

 

Im putting this as an example, just knowing that could be more kind of animals in other more locations

 

Thank you in advance

 

 

1 ACCEPTED SOLUTION

Accepted Solutions
Reeza
Super User
Split them into individual rows using SCAN and then transpose it and replace the missing with 0's. It's fully dynamic for changing amount of animals and names.

location animal
1 dog
1 cat
1 bird

data long;
set have;
n=countw(animals);
do i=1 to n;
animal = scan(animals, i);
count=1;
output;
end;
run;

proc transpose data=long out=wide;
by id;
id animal;
var count;
run;

untested code :(.

View solution in original post

3 REPLIES 3
Reeza
Super User
Split them into individual rows using SCAN and then transpose it and replace the missing with 0's. It's fully dynamic for changing amount of animals and names.

location animal
1 dog
1 cat
1 bird

data long;
set have;
n=countw(animals);
do i=1 to n;
animal = scan(animals, i);
count=1;
output;
end;
run;

proc transpose data=long out=wide;
by id;
id animal;
var count;
run;

untested code :(.
jonatan_velarde
Lapis Lazuli | Level 10
95
96 proc transpose data=long out=wide;
97 by id;
ERROR: Variable ID not found.
98 id animal;
99 var count;
100 run;
Reeza
Super User
Sorry, your By should be by Location.

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