Macro - Conditionally Process some code

[SasStatistics]

The pseudo code below will demonstrate what I would like to do. 

Assume I have a macro of the sort: 

%MyMacro(Part1YesOrNO, Part2YesOrNO); 
   Some code representing "Part 1"; 
      .
      . 
      . 
   Some code representing "Part 2"; 
%mend MyMacro; 

Now, if the user types in: 

%MyMacro(Yes, Yes); 

both parts of the Macro should be run. 

If the user types in:

%MyMacro(Yes, No); 

Only part 1 of the Macro should be run. 

Any advice of how I could achieve this kind of functionality? 

[tbellmer_wf]

%macro mymacro(part1yesorno, part2yesorno);

  %if %upcase(%substr(&part1yesorno, 1, 1)) = Y %then %do;

      /* your part1 code goes here */

  %end;

  %if %upcase(%substr(&part2yesorno, 1, 1) = Y %then %do;

      /* your part2 code goes here */

  %end;

%mend;

%mymacro(Yes, No);

[PaigeMiller · Accepted solution]

%MyMacro(Part1YesOrNO, Part2YesOrNO); 
    %if %upcase(&part1yesorno)=YES %then %do;
   Some code representing "Part 1"; 
    %end;
      . 
   %if %upcase(&part2yesorno)=YES %then %do;   . 
   Some code representing "Part 2"; 
    %end;
%mend MyMacro; 

Hint: don't use such long variable names unless they are absolutely necessary, I would create the macro as follows

%macro mymacro(part1,part2);

unless you are a much better typist than I am, I find shorter name that still have meaning a much better approach, its less typing and less chance for error. Also, I prefer values of Y or N to Yes or No, again simplicity and less typing and less chance for error.

[mkeintz]

Consider:

%MyMacro(Part1YesOrNO, Part2YesOrNO); 
  %if &part1yesorno=Yes %then %do;
     *Some code representing "Part 1"; 
  %end;
  %if &part2yesorno=Yes %then %do;
     *Some code representing "Part 2"; 
  %end;
%mend MyMacro;