I have a very long program, that is taking too long. I figured I would read the LOG back into a data step to search for the steps where the elapsed time is high. In the LOG, you get lines such as
real time 0.02 seconds real time 1:16.09 seconds
so the first step of the program took 2 one-hundredths of a second, while the second step took one minute, 16 and 9/100 seconds.
How to read this in so that the numerical part is recognized as actual times? To simplify even further, here's some relevant code
data a;
input string $ 1-10;
elapsed_time = input(string,time10.2);
cards;
0.02
1:16.09
;
but this seems to turn the 0.02 from the first line into 120 seconds or 2 minutes. The second line isn't converted at all by the informat. What is the proper informat to use here? I want the first line to be converted to 0.02 seconds, and the second line to be converted to 1 minute, 16.09 seconds.
I think you want the STIMER. informat.
Read times in the format as written to the Log from the documentation.
I think you want the STIMER. informat.
Read times in the format as written to the Log from the documentation.
Great Caesar's Ghost! You are correct! I never heard of STIMER before. Thanks.
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