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bncoxuk
Obsidian | Level 7

Hi,

I intend to select those cases which satisfy:

IF regno LIKE ('M%15', 'M%25', 'M%30', 'DISC') THEN OUTPUT;

However, this code is wrong.

How can I accomplish this? Thanks a lot.

1 ACCEPTED SOLUTION

Accepted Solutions
FriedEgg
SAS Employee

The like operator is not available to the if statement only where clauses also I am quite sure it cannot be combined with the in operator to have a list of values.

View solution in original post

4 REPLIES 4
Reeza
Super User

You can only use LIKE in a WHERE clause not an if.

FriedEgg
SAS Employee

The like operator is not available to the if statement only where clauses also I am quite sure it cannot be combined with the in operator to have a list of values.

Ksharp
Super User

An alternative way is to use perl regular expression.

IF prxmatch('/M.*15|M.*25|M.*30|DISC/',regno) THEN OUTPUT;

Ksharp

rosietav
Calcite | Level 5

For what it's worth, I found that using CASE within a PROC SQL SELECT statement worked for me. Sharing the example code in case it is useful.

PROC SQL;
CREATE TABLE SET_A AS

SELECT *, (CASE

                    WHEN FIELD LIKE 'APPL%' THEN 'A'

                    WHEN FIELD LIKE 'SYS%' THEN 'B'

                    ELSE ''

               END

               )

               AS NEW_FIELDNAME

FROM SOURCE_TABLE

WHERE OTHER_CRITERIA = 'XXX';

RUN;

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