Dear all,
I have been facing an issue with one logic, I have a list of dates and amounts, I need to pick the max amount from a same date based on a name.. attached is the example. kindly help in finding the mistake here.. Thank you..
Hello,
data have;
infile cards dlm=',' dsd;
attrib Date format=date9. informat=ddmmyy8.;
length name $10.;
input ID Date name $ Amount Flag_first_name Flag_last_name;
cards;
12345,15082014,Bob,100,0,0
12345,20122016,Bob,200,0,0
12345,20122016,Bob,150,0,1
67890,31012012,John,100,0,0
67890,31012006,John,200,1,0
;
run;
proc sql;
CREATE TABLE want AS
SELECT *
FROM have
WHERE strip(name)="Bob"
GROUP BY name, date
HAVING Amount=max(Amount);
quit;
Hi Gamotte,
Your below program will not work when there is a case like
Bob 21032016 200
Bob 21032016 300
Bob 31122014 500
in this case, your logic will return 500, but the answer I am looking for is 200,
requirement is , when name=bob, date is latest (when latest data is same and has multiple records, then it should return max amount from those).. so the answer should be Bob 21032016 200
kindly advise.
I am not sure i understand the logic you want to implement.
From your description, i would guess the answer should be 300 and not 200.
data have;
infile cards dlm=',' dsd;
attrib Date format=date9. informat=ddmmyy8.;
length name $10.;
input ID Date name $ Amount Flag_first_name Flag_last_name;
cards;
12345,21032016,Bob,200,0,0
12345,21032016,Bob,300,0,0
12345,31122014,Bob,500,0,0
67890,31012012,John,100,0,0
67890,31012006,John,200,1,0
;
run;
proc sql;
CREATE TABLE want AS
SELECT * FROM (
SELECT *
FROM have
WHERE strip(name)="Bob"
GROUP BY name
HAVING Date=max(Date)
)
GROUP BY Name
HAVING Amount=max(Amount);
quit;
Stealing @gamotte's example data:
data have;
infile cards dlm=',' dsd;
attrib Date format=date9. informat=ddmmyy8.;
length name $10.;
input ID Date name $ Amount Flag_first_name Flag_last_name;
cards;
12345,21032016,Bob,200,0,0
12345,21032016,Bob,300,0,0
12345,31122014,Bob,500,0,0
67890,31012012,John,100,0,0
67890,31012006,John,200,1,0
;
run;
proc sort data=have;
by id date amount;
run;
data want;
set have;
by id;
if last.id;
run;
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