I import the data using proc import:
proc import
datafile='/data/bvd/AcademicsSample.txt'
out=bvd.ac
dbms=dlm
replace;
delimiter = '09'x;
run;
One of the extracted variables is Closing_date (proc contents result below):
# Variable Type Len Format Informat
4 Closing_date Num 8 BEST12. BEST32.
From proc print, I see the date as 20081231 for 31 December 2008.
Problem: I cannot extract the year from this date.
I tried using:
1) year=year(Closing_date); result is dots (log NOTE: Invalid argument to function YEAR(20081231) at line 324 column 7.)
2) year=year(datepart(Closing_date)); result is 1960 for all observations (no log NOTE)
3) substr(Closing_date,1,4); result is blanks (log NOTE: Numeric values have been converted to character values at the places given by: (Line):(Column). 324:14)
4) I have tried a bunch of other options that I found online but nothing worked, although I might not have executed these options well
Please help!
This happens because SAS imports Closing_date as a plain number, not a SAS Date.
You can do this to convert to a SAS Date
data have;
date = 20081231;
newdate = input(put(date, 8.), yymmdd8.);
year = year(newdate);
format newdate date9.;
run;
This happens because SAS imports Closing_date as a plain number, not a SAS Date.
You can do this to convert to a SAS Date
data have;
date = 20081231;
newdate = input(put(date, 8.), yymmdd8.);
year = year(newdate);
format newdate date9.;
run;
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