Hi,
I have a dataset with ID and indicators for each month/year (=1 if person had an event in that month, otherwise =.).
ID event_200501 event_200502 event_200503.......event_200912
1 1 1 1 .
2 . . 1 1
I have created an array to identify the earliest month in which a person has an event in each year, like this:
data want;
set have;
array event2005(12) event_200501--event_200512;
do i=12 to 1;
if event2005(i)=1 then earliest_event_2005=i;
end;
/*Etc for all subsequent years*/
run;
The array runs with no error messages and earliest_event_2005 is created, but it's never actually populated (same with all other years). What I want is the exact same data but with new columns indicating the earliest event each person had in each year.
ID event_200501 event_200502 event_200503.......event_200912 earliest_event_2005....earliest_event_2009
1 1 1 1 . 1 .
2 . . 1 1 3 12
Any help is much appreciated.
Hi @Walternate,
The issue with your code is that your iterative DO statement is incomplete:
do i=12 to 1 by -1;
Of course, ballardw's approach is more elegant.
Try this:
data want;
set have;
array event2005(12) event_200501--event_200512;
earliest_event_2005= whichn(min(of event2005(*)), of event2005(*));
run;
Hi @Walternate,
The issue with your code is that your iterative DO statement is incomplete:
do i=12 to 1 by -1;
Of course, ballardw's approach is more elegant.
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.