dates |
2013-08-13,2013-10-18,2013-12-16,2014-03-07,2014-04-30,2014-06-11,2014-07-24,2014-08-11,2014-09-29,2014-11-24,2015-05-05,2015-08-19,2015-10-19,2016-04-15,2016-06-28,2016-10-28,2017-02-13,2017-11-06 |
2020-09-25,2020-10-27,2020-12-08,2021-02-02,2021-04-13,2021-06-08,2022-05-06,2022-07-26,2023-02-28 |
2022-06-27,2022-08-23,2022-11-07,2022-12-13,2023-01-24 |
Let me speak from experience, you will be better off if you have all the dates in one column, rather than separate columns. Many times people choose a poor layout for the data, and wind up causing later programming difficulties. So, a word to the wise, put the dates in a single column.
This code assumes your data is in a SAS data set named HAVE.
data want;
set have;
seq=_n_;
do i=1 to countw(dates,',');
date=input(scan(dates,i,','),yymmdd10.);
output;
end;
format date yymmdd10.;
drop i dates;
run;
Agree with the advice. A small tweak to the solution:
do i=1 to 1 + countw(dates,',');
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