How to use length command with multiple variables

[Sejin]

Hello

I am now trying to use length command with several hundreds of variables.

Since the number of variables are too many, I want to express variables in a short and efficient way.

Following is the code I designed.

length name $ 100 secid $ 100 (time1-204) ($ 100);

I know something is wrong on the last part of the code, but can't figure out how to fix it.

Please give me some help.

[PeterClemmensen]

Close. Do like this

length name $ 100 secid $ 100 time1-time204 $ 100;

[Kurt_Bremser]

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@PeterClemmensen wrote:

Close. Do like this

length name $ 100 secid $ 100 time1-time204 $ 100;

---

Beat me by 15 seconds 🙂

[Kurt_Bremser]

Try

length name $ 100 secid $ 100 time1-time204 $ 100;

[Sejin]

Thanks for the quick reply!

But this is what I got with no outcome..

Do you know what is another error that needs to be fixed?

[PeterClemmensen]

You probably do not see any ERRORS in your log, only NOTES that the variables are uninitialized. You probably need an INPUT Statement after your INFILE Statement.

[Kurt_Bremser]

A SAS log is pure text. To post it here, just use copy/paste into a window opened with the {i} button of the main Rich Text posting window.

The same goes for SAS code, the "little running man icon" will even imitate most of the coloring fo the SAS Enhanced Editor.

And yes, you're missing an input statement.

[novinosrin]

specifying the length of 100 bytes does not require to be done one  by one in a length statement for each variable or variable list:

data w1;
set sashelp.class(drop=name);
length name  secid  time1-time204 $ 100;
run;

proc contents data=w1;
run;

[RW9]

"with several hundreds of variables." - this sounds bad already.  Does the data come from Excel by any chance?  Observations not columns is the way forward.