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Guinaba
Fluorite | Level 6

Hi SAS gurus,

 

May I ask one question how to take today date + 36 months into future? Using the variable below SAS_extension? 

 

data in.indata;

                do year=2010 to year(today());

                                do month=1 to month(today());

                                                SAS_date=mdy(month,1,year);                                                                     

                                                output;

                                end;

                end;

 

                format SAS_date date9.;

run;

 

SAS_extension= SAS_date+36 months *** I would like to take today date + 36 months into future

1 ACCEPTED SOLUTION

Accepted Solutions
Reeza
Super User

INTNX - note the 4th/last parameter aligns it, in this case, I've chosen the beginning of the month. You can choose, end or same. Look up the values in the documentation.

 

date_future36=intnx('month', today(), 36, 'b')

View solution in original post

2 REPLIES 2
Reeza
Super User

INTNX - note the 4th/last parameter aligns it, in this case, I've chosen the beginning of the month. You can choose, end or same. Look up the values in the documentation.

 

date_future36=intnx('month', today(), 36, 'b')
PGStats
Opal | Level 21

data in.indata;

                do year=2010 to year(today());

                                do month=1 to month(today());

                                                SAS_date=mdy(month,1,year);                                                                     

                                                output;

                                end;

                end;

run;

 


are you sure this is what you want?

 

do month=1 to month(today())

 

will return only the months from January to, say, June for ALL years.

 

To get all months, you would do better with:

 

SAS_date = '01JAN2010'd;
do while ( SAS_date <= intnx("MONTH", Today(), 0) );
	SAS_date = intnx("MONTH", SAS_date, 1);
	output;
	end;

 

 

PG

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