BookmarkSubscribeRSS Feed
SAS_INFO
Quartz | Level 8

Hi All,

 

While using substring function, it ignores the trailing blanks , and i need to retain the trailing blanks of the string,

 

ex.

 

data b;

one= "abc ";

two=substr(one,3);

three=lengthc(one);

four=length(two);

run;

this is the output

one two three  four

abc c    7      1

2 REPLIES 2
PGStats
Opal | Level 21

Replace four=length(two) with four=lengthc(two) and you will see that the trailing blanks are kept in variable two.

 

data b;
one= "abc ";
two=substr(one, 3);
three=lengthc(one);
four=lengthc(two);
five = cat('"', two, '"');
run;

proc print; run;
PG
Kurt_Bremser
Super User

When you put a string into a SAS character variable that is shorter than the defined length of the variable, then it is always padded with blanks (unless you use substr() on the left side).

data test;
length x1 $5 x2 $10 x3 $20;
x1 = 'AAAAA';
x2 = 'XXXXXXXXXX';
x3 = put(x2,$hex20.);
output;
x2 = x1;
x3 = put(x2,$hex20.);
output;
run;

proc print data=test noobs;
run;

Result:

 x1      x2                     x3

AAAAA    XXXXXXXXXX    58585858585858585858
AAAAA    AAAAA         41414141412020202020

sas-innovate-2026-white.png



April 27 – 30 | Gaylord Texan | Grapevine, Texas

Registration is open

Walk in ready to learn. Walk out ready to deliver. This is the data and AI conference you can't afford to miss.
Register now and lock in 2025 pricing—just $495!

Register now

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 2 replies
  • 2621 views
  • 2 likes
  • 3 in conversation