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jayakumarmm
Quartz | Level 8

I want to identify previous month full name .i.e. If current month is September then I want to retrieve August. Currently I am going with the below approach but this will fail for the month January. Please assist

 

 

month = month(input("&sysdate9",date9.));
lastmonth = int(month) - 1;
put(lastmonth,nlstrmon.);
1 ACCEPTED SOLUTION

Accepted Solutions
Astounding
PROC Star

Since you have nearly working code, you could tweak it simply:

 

if month = 1 then lastmonth = 12;

else lastmonth = month - 1;

 

If you wanted to get into the depths of how SAS works with dates, you could modify your first statement:

 

lastmonth = month( intnx('month', "&sysdate9"d, -1));

 

As before, that gives you the month number which still has be to converted to the name.

View solution in original post

2 REPLIES 2
set_all__
Fluorite | Level 6

You can use monname format:

 

month_name=PUT(date,monname.);

 

But be aware that this takes a date value as input.

 

format prev_month $20.;
Prev_month = put((INTNX('month', today(), -1, 'B')),monname.);

 

Astounding
PROC Star

Since you have nearly working code, you could tweak it simply:

 

if month = 1 then lastmonth = 12;

else lastmonth = month - 1;

 

If you wanted to get into the depths of how SAS works with dates, you could modify your first statement:

 

lastmonth = month( intnx('month', "&sysdate9"d, -1));

 

As before, that gives you the month number which still has be to converted to the name.

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