How to form the macro application with macro variable

[thanikondharish]

%let sex=F;
%macro &sex;
Proc print data=sashelp.class;
Run;
%mend;

%&sex;

I wrote one application but i am getting error .
Please help to fix this

[PeterClemmensen]

As the %Macro Statement Documentation says: "A macro name must be a SAS name, which you supply; you cannot use a text expression to generate a macro name in a %MACRO statement". 

Which means that you can not use a macro variable in a %Macro Statement.

[thanikondharish]

Thaks,
Is there any other option?

[SASKiwi]

Why do you want to create macros with dynamic names? It makes your code hard. Here is one way:

%let sex=F;
options mprint;

data _null_;
  macro_name = "&sex";
  call execute('%nrstr(%macro '!!macro_name!!';)');
  call execute('%nrstr(proc print data = sashelp.class;run;)');
  call execute('%nrstr(%mend '!!macro_name!!';)');
  call execute('%nrstr(%'!!macro_name!!';)');
run;

You could also write the same statements to an external text file then %INCLUDE them.

[PeterClemmensen]

First of all, why do you want to create a macro with a dynamic name? The dynamic part of a macro should be its arguments.

[Kurt_Bremser]

Even if you could, you don't. It creates unmaintainable code.

DO NOT DO IT. DO NOT EVEN THINK ABOUT IT.

What for do you even think this is needed?

[thanikondharish]

I want to create 3 macro applici at a time
1-F
2-M
3-O

[Kurt_Bremser]

And what is the difference between those macros? You're much better off creating one macro that expects one of F,M,O as a parameter and acts accordingly.