I have the dates like 2018-01, 2014-02, 1996-08, 2012-06, I would like to find the last day of that month (like is 31, 30 , or 28). I believe it also need to include if any leap years are there. Thanks in advance
endMonth = intnx('month', dateVariable, 0, 'e');
Use INTNX and the alignment parameter, E, which will align a date to the end of the month.
@SASuserlot wrote:
I have the dates like 2018-01, 2014-02, 1996-08, 2012-06, I would like to find the last day of that month (like is 31, 30 , or 28). I believe it also need to include if any leap years are there. Thanks in advance
endMonth = intnx('month', dateVariable, 0, 'e');
Use INTNX and the alignment parameter, E, which will align a date to the end of the month.
@SASuserlot wrote:
I have the dates like 2018-01, 2014-02, 1996-08, 2012-06, I would like to find the last day of that month (like is 31, 30 , or 28). I believe it also need to include if any leap years are there. Thanks in advance
Are these character strings, or numeric dates formatted to appear as 2018-01?
The INTNX function makes it easy to determine the last day of the month, if you have numeric dates in a variable which I have creatively named VARIABLENAME. The 'e' tells INTNX to find the last day of the month contained in VARIABLENAME.
last_day_of_month=intnx('month',variablename,0,'e');
thanks it worked
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