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SASuserlot
Barite | Level 11

I have the dates like 2018-01,  2014-02, 1996-08, 2012-06, I would like to find the last day of that month (like is 31, 30 , or 28). I believe it also need to include if any leap years are there. Thanks in advance

1 ACCEPTED SOLUTION

Accepted Solutions
Reeza
Super User
endMonth = intnx('month', dateVariable, 0, 'e');

Use INTNX and the alignment parameter, E, which will align a date to the end of the month.

 


@SASuserlot wrote:

I have the dates like 2018-01,  2014-02, 1996-08, 2012-06, I would like to find the last day of that month (like is 31, 30 , or 28). I believe it also need to include if any leap years are there. Thanks in advance


 

View solution in original post

4 REPLIES 4
Reeza
Super User
endMonth = intnx('month', dateVariable, 0, 'e');

Use INTNX and the alignment parameter, E, which will align a date to the end of the month.

 


@SASuserlot wrote:

I have the dates like 2018-01,  2014-02, 1996-08, 2012-06, I would like to find the last day of that month (like is 31, 30 , or 28). I believe it also need to include if any leap years are there. Thanks in advance


 

SASuserlot
Barite | Level 11
thanks it worked
PaigeMiller
Diamond | Level 26

Are these character strings, or numeric dates formatted to appear as 2018-01?

 

The INTNX function makes it easy to determine the last day of the month, if you have numeric dates in a variable which I have creatively named VARIABLENAME. The 'e' tells INTNX to find the last day of the month contained in VARIABLENAME.

 

last_day_of_month=intnx('month',variablename,0,'e');

 

--
Paige Miller
SASuserlot
Barite | Level 11

thanks it worked

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