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xyxu
Quartz | Level 8

I have a character variable with length $7. I want to convert it into a date variable with yyyymm format. However, the values of the character variable is a bit messy. For examples, there are both "2018-09" and "2018-9". I tried to use 

 

data want;
format date_new yymmn6.;
set have;
date_new = input(date_char, yymmn6.);
run;

but all of the new date variable values are missing.

1 ACCEPTED SOLUTION

Accepted Solutions
Jagadishkatam
Amethyst | Level 16
data want;
input date_char $;
date_new = input(cats(date_char,'-01'), anydtdte10.);
format date_new yymmn6.;
cards;
2018-09
2018-9
;
Thanks,
Jag

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3 REPLIES 3
Jagadishkatam
Amethyst | Level 16
data want;
input date_char $;
date_new = input(cats(date_char,'-01'), anydtdte10.);
format date_new yymmn6.;
cards;
2018-09
2018-9
;
Thanks,
Jag
novinosrin
Tourmaline | Level 20

Use the gorgeous compress with your original idea like

 

data have;
input   date  $;
cards;
2018-09
2018-9
;

data want;
set have;
new_date=input(compress(date,'-'),yymmn6.) ;
format new_date date9.;
run;

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