Hi SAS Community,
I need in your help in the below regard.
I have a data set like this:-
ID | StartDate |
1 | 9-May-12 |
1 | 10-May-12 |
1 | 10-May-12 |
1 | 30-May-12 |
1 | 30-Jun-12 |
2 | 17-May-12 |
2 | 30-May-12 |
2 | 31-May-12 |
2 | 26-Jun-12 |
3 | 26-Jun-12 |
3 | 29-Jun-12 |
3 | 27-Jul-12 |
3 | 25-Aug-12 |
And want an output like this:-
ID | StartDate | Line |
1 | 9-May-12 | 1 |
1 | 10-May-12 | 1 |
1 | 10-May-12 | 1 |
1 | 30-May-12 | 2 |
2 | 17-May-12 | 1 |
2 | 30-May-12 | 1 |
2 | 31-May-12 | 1 |
2 | 26-Jun-12 | 2 |
3 | 26-Jun-12 | 1 |
3 | 29-Jun-12 | 1 |
3 | 27-Jul-12 | 2 |
3 | 25-Aug-12 | 3 |
Basically, The logic is that if there is a gap of more than 20 between the dates by ID then the Line variable should increase by 1.
Thank you for your time and I appreciate your help.
Regards,
SC.
data have;
input ID StartDate :date7.;
format startdate date7.;
datalines;
1 9-May-12
1 10-May-12
1 10-May-12
1 30-May-12
2 17-May-12
2 30-May-12
2 31-May-12
2 26-Jun-12
3 26-Jun-12
3 29-Jun-12
3 27-Jul-12
3 25-Aug-12
;
data want;
set have;
by id;
k=lag(startdate);
if first.id then line=1;
else if intck('day',k,startdate)>=20 then line+1;
drop k;
run;
data have;
input ID StartDate :date7.;
format startdate date7.;
datalines;
1 9-May-12
1 10-May-12
1 10-May-12
1 30-May-12
2 17-May-12
2 30-May-12
2 31-May-12
2 26-Jun-12
3 26-Jun-12
3 29-Jun-12
3 27-Jul-12
3 25-Aug-12
;
data want;
set have;
by id;
k=lag(startdate);
if first.id then line=1;
else if intck('day',k,startdate)>=20 then line+1;
drop k;
run;
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.