How to add one more condition in formula

[Sathish_jammy]

Hi all,

Here I have a sample dataset.

In the calculation method, I get confused in the line which I mention as comment

data have;
input age bmi ht dd;
cards;
25 26.2 176 2
56 25.3 156 1
84 45.2 182 3
57 22.8 145 2
78 32.2 155 5
69 21.6 103 4;

run;

data want;
set have;
value =  
	1.235 +  
	(0.2*age) +  
	(1.13 * (dd=2)*1) + 
	(1.21*ht);
run;

/**(1.13 * dd[yes=1,no=0])) +**/
/**(dd=2,1)YES, (dd=Other dd value)NO**/
/**Here the condition reached for dd=2 so (1.13*1) else dd=(any) (1.13*0)**/

Here the code states dd=2 so (Yes) it taken as 1

How do I add the another one condition for dd=1 in the same parameter. (dd=2,1 (YES) else (NO))

Thanks in advance!

[Astounding]

I can't say whether the logic is correct or not.  But you have to realize that the section you are adding to the formula would add 0 every time, so there is really no need to add it in this case.  At any rate, here's what the additional piece of the formula would look like:

(1.13 * (dd=1) * 0) +

If it's possible that DD could be neither 1 nor 2, you might want:

(1.13 * (dd ne 1) * 0) +

But either way, the net result is adding 0 to the original formula.

[Kurt_Bremser]

(dd=2)

will give you a value of 1 if true, and 0 if false. Multiplying it with 1 solves no purpose.