Hi, I posted a question earlier that was answered by @PaigeMiller , and I got a solution.
However, this new data set has a twist. Some variables have letters attached to them.
The purpose of this is that I was given raw data, and I'm creating an output that condenses information into one variable.
There are 4 subjects, and the "x" represents the value that i want presented in a new variable called CRIT.
So if zzinc3="x", then CRIT=I3.
If zzinc2a="x" and zzexc2b="x" and zzexc3="x" then CRIT=I2A, E2B , E3 ** new twist**
New data with a twist:
data have2;
infile datalines dsd dlm=",";
input subject $ zzinc1 $ zzinc2a $ zzinc2b $ zzinc2c $ zzinc3 $ zzexc1 $ zzexc2a $ zzexc2b $ zzexc3 $;
datalines;
001, x, x, , x, , , x, ,
002, , x, , , x, , , ,
003, , x, , x, , , , ,
004, , , , , x, , , ,x
;
run;
desired output:
subject CRIT
001 I1, I2A, I2C, E2A
002 I2A, I3
003 I2A, I2C,
004 I3, E3
@PaigeMiller 's solution below for part1
data want;
set have;
length crit $ 200;
array zzi zzinc:;
array zze zzexc:;
crit=' ';
do i=1 to dim(zzi);
if zzi(i)='x' then crit=cats(crit,', I',i);
end;
do i=1 to dim(zze);
if zze(i)='x' then crit=cats(crit,', E',i);
end;
if crit=:',' then crit=substr(crit,2);
drop i;
keep subject crit;
run;
link to part1: https://communities.sas.com/t5/SAS-Programming/How-do-I-turn-variables-into-values-for-a-new-variabl...
data want2;
set have2;
length crit $ 200;
array zzi zzinc:;
array zze zzexc:;
crit=' ';
do i=1 to dim(zzi);
if zzi(i)='x' then do;
varname=vname(zzi(i));
crit=cats(crit,', I',substr(varname,6));
end;
end;
do i=1 to dim(zze);
if zze(i)='x' then do;
varname=vname(zze(i));
crit=cats(crit,', E',substr(varname,6));
end;
end;
if crit=:',' then crit=substr(crit,2);
drop i varname;
keep subject crit;
run;
data want2;
set have2;
length crit $ 200;
array zzi zzinc:;
array zze zzexc:;
crit=' ';
do i=1 to dim(zzi);
if zzi(i)='x' then do;
varname=vname(zzi(i));
crit=cats(crit,', I',substr(varname,6));
end;
end;
do i=1 to dim(zze);
if zze(i)='x' then do;
varname=vname(zze(i));
crit=cats(crit,', E',substr(varname,6));
end;
end;
if crit=:',' then crit=substr(crit,2);
drop i varname;
keep subject crit;
run;
Registration is open! SAS is returning to Vegas for an AI and analytics experience like no other! Whether you're an executive, manager, end user or SAS partner, SAS Innovate is designed for everyone on your team. Register for just $495 by 12/31/2023.
If you are interested in speaking, there is still time to submit a session idea. More details are posted on the website.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.