Hello,
I have a data similar to the one below, but without the max3_value column. This is the one I would like to find, but I do not know how.
max3_value takes the last 3 values of the value column (within a group of person) and finds the maximum value of them. Of course, if it is the first or the second observation, it outputs a missing value.
For example: max3_value=10 in period 3 for person A is calculated as a max(10,5,3).
I thought of transposing the data with lagged values, but still I do not know how calculate it within groups of person.
I would kindly appreciate any help.
| person | period | value | max3_value |
| A | 1 | 10 | . |
| A | 2 | 5 | . |
| A | 3 | 3 | 10 |
| A | 4 | 5 | 5 |
| A | 5 | 2 | 5 |
| A | 6 | 3 | 5 |
| A | 7 | 4 | 4 |
| A | 8 | 14 | 14 |
| B | 1 | 6 | . |
| B | 2 | 5 | . |
| B | 3 | 1 | 6 |
| B | 4 | 1 | 4 |
| B | 5 | 4 | 4 |
One way is populate variables with the previous 2 values and keep count of how many obs you have seen for this person.
data want;
set have;
by person ;
lag1=lag1(value);
lag2=lag2(value);
if first.person then cnt=0;
cnt + 1;
if cnt < 3 then max3=.;
else max3 = max(lag1,lag2,value);
run;
One way is populate variables with the previous 2 values and keep count of how many obs you have seen for this person.
data want;
set have;
by person ;
lag1=lag1(value);
lag2=lag2(value);
if first.person then cnt=0;
cnt + 1;
if cnt < 3 then max3=.;
else max3 = max(lag1,lag2,value);
run;
Thank you for prompt response, it works perfectly. ![]()
Why is it obvious that the first two values will be missing? Do you always want them to be?
Also, why is the next to the last value for person A assigned the value 4? Was that supposed to be 14?
You are right, this is not obvious, but that is the way I want them to be (it makes sense in the original dataset).
max3_value=4 is OK, as it is a max(2,3,4).
Tom's suggested code appears to accomplish what you want.
Actually it should be 5 as the max of 5,1,1 is 5.
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