Hi everyone, I've got three variables "a","b","c", I would like to create a list of all possible combinations with these three variables which can be duplicate.The order doesn't matter. It's like factorial problem in high school. eg. 3!=27. The result should be like the following table.I'm really appreciate it if someone can help. Thanks.
seq | Player1 | Player2 | Player3 |
01 | a | a | a |
02 | a | a | b |
03 | a | a | c |
04 | a | b | a |
05 | a | b | b |
06 | a | b | c |
07 | a | c | a |
08 | a | c | b |
09 | a | c | c |
10 | b | a | a |
11 | b | a | b |
12 | b | a | c |
13 | b | b | a |
14 | b | b | b |
15 | b | b | c |
16 | b | c | a |
17 | b | c | b |
18 | b | c | c |
19 | c | a | a |
20 | c | a | b |
21 | c | a | c |
22 | c | b | a |
23 | c | b | b |
24 | c | b | c |
25 | c | c | a |
26 | c | c | b |
27 | c | c | c |
data temp;
do player1='a','b','c';
do player2='a','b','c';
do player3='a','b','c';
output;
end;
end;
end;
run;
Hi.
Does this do what you are asking for?
data temp;
do player1='a','b','c';
do player2='a','b','c';
do player3='a','b','c';
output;
end;
end;
end;
run;
Hi.
Does this do what you are asking for?
Problem solved in a light speed. Thanks!
CALL ALLCOMB
It took me more than 10 minutes to figure it out. I was questioning about myself. Thank you for your reply.
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