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Stalk
Pyrite | Level 9

I would like to extract just the number 27.59 from the following Positive (27.59). Irrespective of the text before the parenthesis.

 

thank you

1 ACCEPTED SOLUTION

Accepted Solutions
Tom
Super User Tom
Super User

SCAN() will work well as long as the text before (or after if searching backwards) does not include parentheses.

number = input(scan(string,1,'()'),32.);

View solution in original post

3 REPLIES 3
Tom
Super User Tom
Super User

SCAN() will work well as long as the text before (or after if searching backwards) does not include parentheses.

number = input(scan(string,1,'()'),32.);
jimbarbour
Meteorite | Level 14

It sounds like you know the number that you are searching for in advance; is that correct?  If so, see the code below.  I'm using a combination of the FIND, LENGTH, and SUBSTR functions.  I'm sure there are other ways to do it as well.

 

Regards,

 

Jim

 

Results:

jimbarbour_0-1622057293236.png

Code:

DATA	_NULL_;
	Search_For	=	'27.59';
	Search_Len	=	LENGTHN(Search_For);
	Var			=	'Positive (27.59)';

	Number	=	SUBSTR(Var, FIND(Var,'27.59'), Search_Len);

	PUTLOG	"NOTE:  "  Number=;
	PUTLOG	"NOTE-  "  ;
RUN;
Stalk
Pyrite | Level 9

Thank you Tom and Jim for the quick response. 

 

I used the following..ct_value= scan(Result,2,'()');

I just need the number with in parenthesis for all the records. 

 

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