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kaushik_patra
Obsidian | Level 7

I am using the following syntax to calculate the minutes between two time variable.

INFTIME = INTCK('MINUTE',INPUT(EXSTTM,TIME8.),INPUT(EXENTM,TIME8.));

 

EXSTTM = 23:48

EXENTM = 00:48

The result is coming out as -1380 but I expect the result to be 60 min obviously. Guess the problem is the end time 00:48 which is the next day. Any suggestion?

1 ACCEPTED SOLUTION

Accepted Solutions
Jagadishkatam
Amethyst | Level 16
data have ;
EXSTTM = '23:48't;
EXENTM = '00:48't;
if EXENTM lt EXSTTM then duration=('24:00't-EXSTTM)+EXENTM; 
else duration=intck('minute',EXSTTM,EXENTM);
format EXSTTM EXENTM duration time5.;
run;
Thanks,
Jag

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4 REPLIES 4
Jagadishkatam
Amethyst | Level 16
data have ;
EXSTTM = '23:48't;
EXENTM = '00:48't;
if EXENTM lt EXSTTM then duration=('24:00't-EXSTTM)+EXENTM; 
else duration=intck('minute',EXSTTM,EXENTM);
format EXSTTM EXENTM duration time5.;
run;
Thanks,
Jag
kaushik_patra
Obsidian | Level 7

Thanks Jag. It worked; I had to do a minor tweak to divide it by 60 as the duration is calculated in seconds and I wanted it to be in minutes.

Kaushik

ballardw
Super User

If you are going to compare times across midnight you will need to incorporate a DATE portion, make a datetime value and then you can use intnx function to return minutes between directly using the 'minute' interval.

kaunth
Calcite | Level 5

what if EXSTTM=03:38

and EXENTM=03:18 which is on the same day then this code will create problems.

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