Determining if 3rd character is a letter or number?

[That____Redhead]

Hey all,

I can't seem to find a quick way of doing this.  I have a string variable, and if the 3rd character is a number, it is indicative of a business, if it is a letter it is an individual.  What is the easiest way to determine this?

I have tried marker = (substr(var,3,1) IN(0:9)); but then when it's text, it gives errors.

Thanks!    

[Haikuo · Accepted solution]

Try this:

data have;

input string$ @@;

cards;

adsflk ad2eif ad0euh

;

data want;

set have;

Digiornot=anydigit(substr(string,3,1));

put '1-Digit 0-None Digit' digiornot=;

run;

Haikuo

[That____Redhead]

Thanks!