Hi,
I could not find a solution for this problem on the board so I thought I would ask instead.
As the long subject line says,
If a variable A meets certain conditions then I want to delete all observations with the same variable B as the other observation.
If A >10 and B is 5, then I want to remove all variables where B=5.
I want this
Obs A B
1 5 10
2 11 10
3 1 11
4 9 11
5 12 12
6 3 13
To become this
1 1 11
2 9 11
3 3 13
Thanks in advance!
Here you go:
data have;
input a b;
datalines;
5 10
11 10
1 11
9 11
12 12
3 13
;
data want;
if _n_=1 then
do;
dcl hash h1(dataset:'have(where=(a>10))');
h1.defineKey('b');
h1.defineDone();
end;
set have;
if h1.check()=0 then delete;
run;
proc print data=want;
run;
I don't see one obs where B=5?
Here you go:
data have;
input a b;
datalines;
5 10
11 10
1 11
9 11
12 12
3 13
;
data want;
if _n_=1 then
do;
dcl hash h1(dataset:'have(where=(a>10))');
h1.defineKey('b');
h1.defineDone();
end;
set have;
if h1.check()=0 then delete;
run;
proc print data=want;
run;
Ok. I would go with the solution by @Patrick then.
Alternatively you could do
data have;
input a b;
datalines;
5 10
11 10
1 11
9 11
12 12
3 13
;
data want;
array _ {1000000} _temporary_;
do until (lr1);
set have(where=(a>10)) end=lr1;
_[b]=1;
end;
do until (lr2);
set have end=lr2;
if _[b] ne 1 then output;
end;
stop;
run;
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.