data have;
length Group $50;
input Group $ _NAME_ $ Value date $;
datalines;
wwww AARP 50 1jun2018
2fff BBRP 123 5may2015
;
run;
data have1;
set have;
date1 = input(date,anydtdte11.);
format date1 date9.;
run;
I am attempting to change the date format to read as a DDMMMYYYY format. I tried several combinations including
format date1 ddmmmyyyy10.
What about:
format date1 ddmmyyn8.;
In an INPUT statement you need an INFORMAT, which should reflect what the date looks like.
This works for me. Please put your code in a code block in the future, it helps avoid issues when copy/pasting for testing.
data have; length Group $50; input Group $ _NAME_ $ Value date $; datalines; wwww AARP 50 1jun2018 2fff BBRP 123 5may2015 ; run; data have1; set have; date1 = input(date,date9.); format date1 date9.; run;
Hi:
Or, as an alternative, you could use an INFORMAT directly in the INPUT statement:
Either approach will work. I tend to use ANYDTDTE if I'm not certain that all the date values in the DATALINES appear the same.
Cynthia
You didn't define a length for your character variable DATE. So SAS will default it to length $8, which will truncate values with two digit days and four digit years. Not sure why you defined a length for one of your variables but not the other three. Best to define the lengths yourself and not force SAS to guess at what you want.
data have;
length Group $50 _name_ $32 value 8 date $11;
input Group _NAME_ Value date;
datalines;
wwww AARP 50 11jun2018
2fff BBRP 123 15-may-2015
;
Hopefully your real character variable is at least 9 characters long (or 11 if the date strings have punctuation around the month code).
data have1;
set have;
length date1 8;
date1 = input(date,date11.);
format date1 date9.;
run;
Obs Group _name_ value date date1 1 wwww AARP 50 11jun2018 11JUN2018 2 2fff BBRP 123 15-may-2015 15MAY2015
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