Hello,
I want to build a macro which shows me current date in datetime format and a date -1 month.
%let date1 = %sysfunc(datetime(),DATETIME16.);
%let date_prev=%sysfunc(intnx(month,"%sysfunc(putn("&date1"d,DATETIME16.))"d,-1,s),DATETIME16.);
%put &date_prev.;
Date1 gives me good results but in date_prev i have 31DEC59:23:53:55.
How I should change this macro to have date_prev = 07AUG2017time ?
Why not do it in a data step like this?
data _null_;
date1 = datetime();
date_prev = intnx('dtmonth', date1, -1, 's');
format date1 date_prev datetime16.;
put date1= date_prev=;
run;
Why not do it in a data step like this?
data _null_;
date1 = datetime();
date_prev = intnx('dtmonth', date1, -1, 's');
format date1 date_prev datetime16.;
put date1= date_prev=;
run;
Its been asked many times here. The question is why would you need to? You can always get yesterdays date by doing intnx('year',today,-1); so why bother going through all the effort of calculating it, then storing it as text - macro is always text - then trying to use that text in your code. Its madness.
April 27 – 30 | Gaylord Texan | Grapevine, Texas
Walk in ready to learn. Walk out ready to deliver. This is the data and AI conference you can't afford to miss.
Register now and save with the early bird rate—just $795!
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.