BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
SarahW13
Obsidian | Level 7

Hello all,

 

I am trying to figure out how to create a sequence variable that is based on two other variables (med [a categorical variable] and date)

 

Below is what I have:

 

id           med            date

1            A                 01/01/2019

1            A                 02/01/2019

1            B                 04/01/2019

1            B                 05/01/2019

1            A                 06/01/2019

1            A                 07/01/2019

2            A                 03/01/2019

2            C                 04/01/2019

2            A                 06/01/2019

 

Below is what I want:

id           med            date                 Seq

1            A                 01/01/2019     1

1            A                 02/01/2019     1

1            B                 04/01/2019     2

1            B                 05/01/2019     2

1            A                 06/01/2019     3

1            A                 07/01/2019     3

2            A                 03/01/2019     1

2            C                 04/01/2019     2

2            A                 06/01/2019     3

 

Since id#1 received med A first, when that person switched to med B for a period of time, I want that period on med B to be seq #2. Even when that person switched back to med A again, since s/he already received med B, I want the new start of med A to be indicated with seq #3 and not seq#1.

 

Any advice?

Thanks in advance!

1 ACCEPTED SOLUTION

Accepted Solutions
PaigeMiller
Diamond | Level 26
proc sort data=have;
    by id date;
run;

data want;
    set have;
    by id;
    prev_med=lag(med);
    if first.id then count=1;
    if not first.id and med^=prev_med then count+1;
    drop prev_med;
run;
--
Paige Miller

View solution in original post

2 REPLIES 2
PaigeMiller
Diamond | Level 26
proc sort data=have;
    by id date;
run;

data want;
    set have;
    by id;
    prev_med=lag(med);
    if first.id then count=1;
    if not first.id and med^=prev_med then count+1;
    drop prev_med;
run;
--
Paige Miller
Ksharp
Super User
data have;
input id           med    $        date :	$10.;
cards;
1            A                 01/01/2019
1            A                 02/01/2019
1            B                 04/01/2019
1            B                 05/01/2019
1            A                 06/01/2019
1            A                 07/01/2019
2            A                 03/01/2019
2            C                 04/01/2019
2            A                 06/01/2019
;

data want;
 set have;
 by id med notsorted;
 if first.id then seq=0;
 seq+first.med;
run;

hackathon24-white-horiz.png

The 2025 SAS Hackathon has begun!

It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.

Latest Updates

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 2 replies
  • 682 views
  • 1 like
  • 3 in conversation