Hi all,
I'd like to create a indicator variable for the following data set:
ID Year Var1 Indicator
A 1990 . 1
A 1991 1 1
A 1992 2 1
B 1990 . 0
B 1991 0 0
B 1992 1 0
I want to set the indicator equals to 1 as long as any observation on Var1 within a particular group ID shows a value of 2, as shown in the sample data.
How can I program it in SAS? I appreciate any help.
Han
And if you have higher values than 2 as in the below modified example, binary operation is still very simple-->
data have;
infile datalines truncover;
input ID $ Year Var1;
datalines;
A 1990 . 1
A 1991 1 1
A 1992 2 1
A 1993 3 .
B 1990 . 0
B 1991 0 0
B 1992 1 0
;
proc sql;
create table want as
select *, max(var1=2) as indicator
from have
group by ID
order by 1, 2;
quit;
SQL is likely your best bet here:
proc sql;
create table want as
select *, case when max(var1)=2 then 1 else 0 as indicator
from have
group by ID
order by 1, 2;
quit;
Thank you for the prompt rely.
I followed your codes using the variables and data set I have:
proc sql;
create table c7 as
select *, case when max(row2yrs)=2 then 1 else 0 as rowtag
from c6
group by execid
order by gvkey, year;
quit;
It prompted error:
822 proc sql;
823 create table c6 as
824 select *, case when max(row2yrs)=2 then 1 else 0 as rowtag
--
73
ERROR 73-322: Expecting an END.
825 from c6
826 group by execid
827 order by gvkey, year;
828 quit;
How can I resolve it? Many thanks!
Well....I forgot the END but the log told you that. Add in the word END before the word AS.
ERROR 73-322: Expecting an END
@Zerg While I completely agree with @Reeza with sql option assuming 2 is your max within a group ID, you can avoid case when for the reason you are anyways remerging. This helps binary operations
data have;
infile datalines truncover;
input ID $ Year Var1;
datalines;
A 1990 . 1
A 1991 1 1
A 1992 2 1
B 1990 . 0
B 1991 0 0
B 1992 1 0
;
proc sql;
create table want as
select *, max(var1)=2 as indicator
from have
group by ID
order by 1, 2;
quit;
And if you have higher values than 2 as in the below modified example, binary operation is still very simple-->
data have;
infile datalines truncover;
input ID $ Year Var1;
datalines;
A 1990 . 1
A 1991 1 1
A 1992 2 1
A 1993 3 .
B 1990 . 0
B 1991 0 0
B 1992 1 0
;
proc sql;
create table want as
select *, max(var1=2) as indicator
from have
group by ID
order by 1, 2;
quit;
Like your log showed, the end statement was missing. However, is 2 the maximum value? If not, you could use something like:
data have (drop=indicator);
input ID $ Year Var1 Indicator;
cards;
A 1990 . 1
A 1991 1 1
A 1992 2 1
B 1990 . 0
B 1991 0 0
B 1992 1 0
;
proc sql;
create table want (drop=twovar) as
select a.*,max(b.twovar) as twovar,
case
when not missing(twovar) then 1
else 0
end as indicator
from have a left join have (rename=(Var1=twovar) drop=year where=(twovar eq 2)) b
on a.ID eq b.ID
group by a.ID
order by 1, 2
;
quit;
Art, CEO, AnalystFinder.com
data have (drop=indicator);
input ID $ Year Var1 Indicator;
cards;
A 1990 . 1
A 1991 1 1
A 1992 2 1
B 1990 . 0
B 1991 0 0
B 1992 1 0
;
data want;
merge have have(keep=id var1 rename=(var1=_var1) where=(_var1=2) in=inb);
by id;
flag=inb;
drop _var1;
run;
proc print noobs;run;
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