Hi folks,
Probably a common problem, and I'm just blanking on a solution that doesn't require 5,040 lines of code...
I have seven variables, of which any number of them can be populated or missing. In any combination. And I'd like to concatenate them into a single variables that displays the populated values as a list separated by commas. But obviously I don't want extraneous commas, so I only want the new variable to include non-missing values. Any thoughts on how to do this?
Original data:
| Obs | Barrier1 | Barrier2 | Barrier3 | Barrier4 | Barrier5 | Barrier6 | Barrier7 |
|---|---|---|---|---|---|---|---|
| 1 | Child | Funding | Title IV-E | ||||
| 2 | Funding | Courts | Team | ||||
| 3 | Policy | Team | Other | ||||
| 4 | Child | Courts | |||||
| 5 | Funding | Policy | |||||
| 6 | Child | Courts | Title IV-E | Other |
Desired new variable:
| Obs | Barriers |
|---|---|
| 1 | Child, Funding, Title IV-E |
| 2 | Funding, Courts, Team |
| 3 | Policy, Team, Other |
| 4 | Child, Courts |
| 5 | Funding, Policy |
| 6 | Child, Courts, Title IV-E, Other |
call catx function
call catx function
Oh, duh. It really is a Friday isn't it... where is my brain? I'm so used to using the long-hand version with the concatenation operator I completely forgot about the catx function. Thanks! ![]()
(That's 2 for 2 today, Reeza.)
I would start with CATX function in a data step
data want;
set have;
length combinedBarriers $ <big enough integer to store longest combination>;
combinedbarriers = catx(',' of Barrier1-Barrier7);
run;
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