Counting number of days without repeat

[Moraes86]

Hi all,

I am wondering to count how many days an event occurred.
In this example, the interval between the first day and the last days is 20 days.

So, there are repeatable days; thus, I would like to know how many days this event occurs.
For example, in this case, it occurred in 10 days, even it was 20 days interval. Therefore, I wish to get this result: 10 days.

Thanks all

data want ;

set have; ;

by id date ; (I think it is right)

/* this part that I am not sure */

run;

HAVE			WANT
id	date		id	date	Number of days
A	13-Sep-19		A	13-Sep-19	10
A	18-Sep-19		A	18-Sep-19
A	18-Sep-19		A	18-Sep-19
A	18-Sep-19		A	18-Sep-19
A	18-Sep-19		A	18-Sep-19
A	19-Sep-19		A	19-Sep-19
A	19-Sep-19		A	19-Sep-19
A	24-Sep-19		A	24-Sep-19
A	25-Sep-19		A	25-Sep-19
A	25-Sep-19		A	25-Sep-19
A	25-Sep-19		A	25-Sep-19
A	25-Sep-19		A	25-Sep-19
A	25-Sep-19		A	25-Sep-19
A	27-Sep-19		A	27-Sep-19
A	27-Sep-19		A	27-Sep-19
A	30-Sep-19		A	30-Sep-19
A	30-Sep-19		A	30-Sep-19
A	30-Sep-19		A	30-Sep-19
A	1-Oct-19		A	1-Oct-19
A	1-Oct-19		A	1-Oct-19
A	2-Oct-19		A	2-Oct-19
A	2-Oct-19		A	2-Oct-19
A	2-Oct-19		A	2-Oct-19
A	3-Oct-19		A	3-Oct-19
A	3-Oct-19		A	3-Oct-19

[PaigeMiller · Accepted solution]

Untested code

proc sql noprint;
    select id,count(distinct date) from have
    group by id;
quit;

From now on, please do not provide data as screen captures. We strongly prefer data provided as SAS data step code (instructions). This allows us to send you TESTED code, rather than untested code, which the above is.

[Moraes86]

Thank you very much PaigeMiller!
It worked!!