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I would like to know how I can convert this formula into SAS code? Thanks in advance

bio.cov <- bio.cov %>% mutate(female = ifelse(sex == 0, TRUE, FALSE),

                   kappa=ifelse(female, 61.9, 79.6),

                   alpha=ifelse(female,-0.329,-0.411),

                   srblack = ethnicity %in% c(4, 4001,4002,4003),

                   eGFR = 141 * pmin(creatinine/kappa, 1)^alpha *

                                pmax(creatinine/kappa, 1)^-1.209 *

                                0.993^age * ifelse(female, 1.018, 1) *

                                ifelse(srblack, 1.159, 1))
1 ACCEPTED SOLUTION

Accepted Solutions
japelin
Rhodochrosite | Level 12

how about this code?

But not tested because I don't know data structure and have no data.

 

 

data bio;
  set bio;
  female=ifn(sex=0, 1, 0);
  kappa =ifn(female, 61.9, 79.6);
  alpha =ifn(female,-0.329,-0.411);
  srblack=ifn(ethnicity in (4,4001,4002,4003),1,0);
  eGFR = 141 * min(creatinine/kappa, 1)**alpha *
               max(creatinine/kappa, 1)**-1.209 *
               0.993**age * ifn(female, 1.018, 1) *
               ifn(srblack, 1.159, 1);
run;

 

 

View solution in original post

4 REPLIES 4
japelin
Rhodochrosite | Level 12

how about this code?

But not tested because I don't know data structure and have no data.

 

 

data bio;
  set bio;
  female=ifn(sex=0, 1, 0);
  kappa =ifn(female, 61.9, 79.6);
  alpha =ifn(female,-0.329,-0.411);
  srblack=ifn(ethnicity in (4,4001,4002,4003),1,0);
  eGFR = 141 * min(creatinine/kappa, 1)**alpha *
               max(creatinine/kappa, 1)**-1.209 *
               0.993**age * ifn(female, 1.018, 1) *
               ifn(srblack, 1.159, 1);
run;

 

 

mantubiradar19
Quartz | Level 8

Hi Kawakami, 

 

Thanks for your help, suppose if my data doesn't have the information for ethnicity, can I write the formula like this?

data bio;
  set bio;
  female=ifn(sex=0, 1, 0);
  kappa =ifn(female, 61.9, 79.6);
  alpha =ifn(female,-0.329,-0.411);
  eGFR = 141 * min(creatinine/kappa, 1)**alpha *
               max(creatinine/kappa, 1)**-1.209 *
               0.993**age * ifn(female, 1.018, 1)
run;
japelin
Rhodochrosite | Level 12

I think it's fine.

You're just missing a semicolon at the end.

 

               0.993**age * ifn(female, 1.018, 1);
mantubiradar19
Quartz | Level 8
Thank you very much ~ let me try this code!

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