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JohnChen_TW
Quartz | Level 8

Hi all,

 

I'm trying to compress a data like "<= 0.3" to "0.3", but COMPRESS FUNCTION seems that just can compress ALL punctuation marks at one time...So, is there any better way to compress only "<= " and keep the decimal? 

 

However, this is just one example of my data. I need a resolution for all cases like this. Thank you!

 

 

 

Original    Compressed

<= 0.3             0.3

  0.58             0.58

 > 1.2              1.2

   45                45

1 ACCEPTED SOLUTION

Accepted Solutions
RW9
Diamond | Level 26 RW9
Diamond | Level 26

Well, its likely that you have other maths symbols, so maybe reverse the thinking, the below "k"eeps, only "d"igits and the decimal:

data test;
  original = "<= 0.3";
  compressed = compress(original,'.','kd');
run;

View solution in original post

6 REPLIES 6
JohnChen_TW
Quartz | Level 8
Well, this will resolve only the first line of data. Thank you.
Kalind_Patel
Lapis Lazuli | Level 10

Hi @JohnChen_TW;

 

You can use this line :

compressed = compress(original,'<=');

 

this will remove <= combination from the variaable;

 

But, on the third line you provided another special character in sample data,

so below code will not compress this special character;

 

so in this case you can use this code:

data test;
set test;
compressed=compress(original,'<');
compressed=compress(original,'=');
compressed=compress(original,'>');
run;

 

it will remove all the possible combination like: <=, <, =, >, => from the variable

 

 

 

JohnChen_TW
Quartz | Level 8
Kalind_Patel, thanks for your suggestion.
Well, maybe my question is unclear. The point is that I need to keep only "0.1", "1.5", ...and so on.
Thank you.
RW9
Diamond | Level 26 RW9
Diamond | Level 26

Well, its likely that you have other maths symbols, so maybe reverse the thinking, the below "k"eeps, only "d"igits and the decimal:

data test;
  original = "<= 0.3";
  compressed = compress(original,'.','kd');
run;
JohnChen_TW
Quartz | Level 8
Hi RW9,

Thanks for your answer! It resolved my question. 🙂

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