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K_S
Quartz | Level 8 K_S
Quartz | Level 8

Hello!

i have a database that looks like this:

 

idnum  text1   text2   text3   text4   text5   text6   text7.....text35

1          bsf       ttg      Hht     Hht      Hhp.   Ppj      Ggt       Tty

2           Yyy.     Hjs.   Hht     Tty       Hgy.    Xyz.    Yyu.     Kio 

.

.

what i want to do is this, but in a practical way:

if text1 in (‘Hht’, ‘Tty’, ‘kyo’)  or text2 in  (‘Hht’, ‘Tty’, ‘kyo’)  or text3 in  (‘Hht’, ‘Tty’, ‘kyo’)  ......or text35 in  (‘Hht’, ‘Tty’, ‘kyo’)  then new_var=1;

else new_var=0;


any tips?

 

1 ACCEPTED SOLUTION

Accepted Solutions
novinosrin
Tourmaline | Level 20
data want;
 set have;
 array j text:;
 do t='Hht', 'Tty', 'kyo';
  new_var= t in j ;
  if new_var then leave;
 end;
 drop t;
run;

View solution in original post

3 REPLIES 3
novinosrin
Tourmaline | Level 20
data want;
 set have;
 array j text:;
 do t='Hht', 'Tty', 'kyo';
  new_var= t in j ;
  if new_var then leave;
 end;
 drop t;
run;
s_lassen
Meteorite | Level 14

There are many ways to skin a cat. The shortest code is probably this:

data want;
  set have;
  new_var=whichc('Hht',of text1-text35) or whichc('Tty',of text1-text35) or whichc('kyo',of text1-text35);
run;

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