Compare the date with macro date

[SASdevAnneMarie]

Hello Experts,

I create the macro variable in this way :

%let DatePublication = %sysfunc(today(), ddmmyy10.);
%put &DatePublication.;

But when I apply this condition :

if datepart(d_fin) > &DatePublication.

Unfortunately, I don't have the right observation in output. Do I need apply another function? 

When I apply %eval it also doesn't work. The format of d_fin is datetime22. format. Thank you for your help.

if datepart(d_fin) > %eval(&DatePublication.)

[AMSAS]

In short you are not comparing apples to apples.
The macro variable DatePublication contains a formatted date (character value e.g. 13/06/2023)

Whereas the datepart function is returning a SAS date value (numeric number of days since 01 Jan 1960) from a SAS date/time value

Run the following code in SAS and compare the log output

Unless you have some reason for using the macro variable I would remove that additional complexity from the code (see 2nd data step in example below)

%let DatePublication = %sysfunc(today(), ddmmyy10.); 
%put &DatePublication.; 

data _null_ ; 
  datetime=datetime() ; 
  datepart=datepart(datetime) ; 
  put datetime= ; 
  put datepart= ; 
run ; 

data _null_ ; 
  datetime=datetime() ; 
  datepart=datepart(datetime) ; 
  do date=date()-1 to date()+1 ; 
    if date>datepart(datetime) then 
      put "Date " date " > DateTime " datetime " - DatePart " datepart ; 
    else 
      put "Date " date "<= DateTime " datetime " - DatePart " datepart ; 
  end ; 
run ; 

[russt_sas]

You just need to remove the format from your statement, try changing it to this:

%let DatePublication = %sysfunc(today());

[PaigeMiller]

%let DatePublication = %sysfunc(today(), ddmmyy10.);

The macro variable &DatePublication is not a valid SAS date. It is the text string 13/06/2023. SAS does not recognize this as a date, even though humans do recognize this as a date.

SAS dates are the number of days since 01JAN1960, and so SAS would recognize this as a valid SAS date.

%let DatePublication = %sysfunc(today());

This is the value 23174, which is a valid SAS date. It is the number of days since 01JAN1960. 

So when you compare a date value in your DATA step, SAS always uses its internal representation of the number of days since 01JAN1960. Thus if you use this particular &DatePublication, this should work in your DATA step.

See Maxim 28: "Macro variables need no formats."

[Tom]

The macro variable &DatePublication is not a valid SAS date. It is the text string 13/06/2023. SAS does not recognize this as a date, even though humans do recognize this as a date.

Some humans might.  My calendar only has 12 months in a year so 13/06/2023 does not look like a date to me.

🙂 

[Tom]

When working with macro variables make sure the generate valid code.  If I run these two statements:

%let DatePublication = %sysfunc(today(), ddmmyy10.);
%put &DatePublication.;

I see 13/06/2023 printed in the SAS log.

Does this look like valid SAS code?

if datepart(d_fin) > 13/06/2023

You are dividing 13 by 6 and then again by 2023.

To convert 13/06/2023 back into a date you would need to use the INPUT() function.

if datepart(d_fin) > input("&DatePublication.",ddmmyy10.)