Change the Field value

[cho16]

Hi,

I have the field name called CIN and CLIENT_ID.

If the program type as “E” then the ID formatted XX12345X, should be sent in the CIN field instead of CLIENT_ID

If the program type as “E” then the  ID formatted 70017001, should be sent in the CLIENT_ID field instead of CIN.

CIN : 8 alpha numeric (ex.XX02345X)

CLIENT_ID: 8 numeric (ex.70005234)

Program type	CLIENT_ID	CIN	Membno
E	NF01984Y		42500000
E	AB09099Y		43567899
E		70017984	56798000

Need to show as below values:

Program type	CLIENT_ID	CIN	Membno
E		NF01984Y	42500000
E		AB09099Y	43567899
E	70017984		56798000

Thanks in Advance

[Shmuel]

Is there a variable containing the program type 'E' ? If yes - what is its name ?

My first thought was that you just need rename of the two variables:

data want;

 set have(rename=(CIN=Client_id Client_id=CIN));

run;

If rename do the work, then even better is to use PROC DATASETS to renmae the varible names.

It is much faster and saves disk space (eliminates copy of the dataset);

[Ksharp · Accepted solution]

data have;
input (Program 
CLIENT_ID
CIN
Membno) (: $20.);
cards;
E
NF01984Y
. 
42500000
E
AB09099Y
. 
43567899
E
. 
70017984
56798000
;
run;

data want;
 set have;
 if not missing(client_id) then do;
  if prxmatch('/^[a-z][a-z]\d{5}[a-z]$/i',strip(client_id)) then new_cin=client_id;
  if prxmatch('/^\d{8}$/',strip(client_id)) then new_id=client_id;
 end;
 
 if not missing(cin) then do;
  if prxmatch('/^[a-z][a-z]\d{5}[a-z]$/i',strip(cin)) then new_cin=cin;
  if prxmatch('/^\d{8}$/',strip(cin)) then new_id=cin;
 end;
run;

[cho16]

Thanks Sharp ! .