Challenging SAS date format

[frupaul]

Hi everyone,

Please can someone help me out. I am trying to extract the datepart of the following date values (please note they come up as character values in the dataset Im dealing with):

19/07/2018 09:34:02 AM

18/07/2018 09:19:50 PM

13/07/2018 06:28:39 PM

12/07/2018 09:58:06 AM

12/07/2018 08:54:34 AM

So what I am expecting to achieve to create a new field, with values

19/07/2018

18/07/2018

13/07/2018

12/07/2018

12/07/2018

Please can anyone give any suggestions.

Thanks,

Paul

[Kurt_Bremser · Accepted solution]

Use

newdate = input(substr(datestring,1,10),ddmmyy10.);
format newdate ddmmyy10.;

[Swagat711]

Hope below query solve your problem

data abc;
input datetime $23.;
datalines;
19/07/2018 09:34:02 AM
18/07/2018 09:19:50 PM
13/07/2018 06:28:39 PM
12/07/2018 09:58:06 AM
12/07/2018 08:54:34 AM
run;

data test;
set abc;
date_new=input(scan(datetime,1,''),ddmmyy10.);
format date_new ddmmyy10.;
run;