Caluculating number of days between two dates

[rakeshvvv]

Hi ,

I wuould like calculate the number of days between the first visit and last visit for a subject. The data lookis like this.

Patno     startdate                         Visit

1000       2013-03-21T08:03                1

1000       2013-03-27T23:30                2

1000       2013-060-04T20:30               3

Thanks

Rocky

[Reeza]

What should the output look like?

[rakeshvvv]

the output should be in a separet collmns with numbers of day as intezer value

[Reeza]

Here's a way to calculate it. I'll let you figure out how to get it into your data. Also, what if a person has only 1 visit?

proc sql;

create table duration as

select a.patno, max(datepart(startdate))-min(datepart(startdate)) as duration

from have

group by patno

having count(patno)>1;

quit;

[rakeshvvv]

Thanks for the reply.... the problem i am facing with data is that date is in 2013-07-10T08:30 format.......as it is character variable...we were not able aplly difference function.....that pasrticular date needs to converetd to sas date and then we need subtract from one another but I am not usrehow to convert that particular date to sas date and then again converting the difference to number of day....hope this helps.....

[Reeza]

It helps if you start off with that...

Your date time is ISO 8601 format, the T notation usually gives it away.

proc sql;

create table duration as

select a.patno, max(datepart(input(startdate, E8601DT19.)))-min(datepart((input(startdate, E8601DT19.))) as duration

from have

group by patno

having count(patno)>1;

quit;

[yeshwanth]

I never worked on the datetime format which you have specified. But if you can change the format to date9. then its pretty simple.

Here I assume, the date of the second visit cannot be greater than the third.

data k1;
informat startdate DATE9.;
FORMAT STARTDATE DATE9.;
input Patno startdate  Visit;
cards;
1000 05JAN2013 1
1000 08JAN2013 2
1000 25JAN2013 3
;
run;

PROC SQL;
CREATE TABLE K2 AS
SELECT MAX(STARTDATE)-MIN(STARTDATE) AS DATE_DIFF
FROM K1
GROUP BY PATNO;
RUN;

Hope this helps !!

[Tom]

First you have to have valid dates.  The last observation has an extra zero.

You can use INTCK to calculate intervals.

data have ;

  length patno 8 startdate $20 visit 8;

  input Patno startdate Visit ;

cards;

1000 2013-03-21T08:03 1

1000 2013-03-27T23:30 2

1000 2013-06-04T20:30 3

;;;

data want ;

  set have ;

  by patno ;

  date=input(startdate,E8601DT19.);

  format date sdate datetime20.;

  if first.patno then sdate=date;

  retain sdate ;

  diff = intck('dtday',sdate,date);

  put (patno visit startdate diff) (=);

run;

patno=1000 visit=1 startdate=2013-03-21T08:03 diff=0

patno=1000 visit=2 startdate=2013-03-27T23:30 diff=6

patno=1000 visit=3 startdate=2013-06-04T20:30 diff=75