I have a table that is sorted by a date column. In a new column (called interval), I want to be able to calculate the number of days between the date in the subsequent record. I feel like there has to be a simple way to do this, but I can't figure it out.
i.e. the first record would always be 0. Then it is 32 days from 6/17/2020 to 7/19/2020, and then 94 days from 7/19/2020 to 10/21/2020, etc.
data have;
input id latestdt :yymmdd10.;
format latestdt yymmddd10.;
datalines;
1 2020-06-17
2 2020-07-19
3 2020-10-21
4 2020-10-26
5 2020-11-05
6 2020-11-13
7 2020-11-13
;
run;
data want;
input id latestdt :yymmdd10. interval;
format latestdt yymmddd10.;
datalines;
1 2020-06-17 0
2 2020-07-19 32
3 2020-10-21 94
4 2020-10-26 5
5 2020-11-05 10
6 2020-11-13 8
7 2020-11-13 0
;
run;
data want;
set have;
interval=latestdt-lag(latestdt);
run;
@csanfor2 DIF function is rather straight forward i would think-
data have;
input id latestdt :yymmdd10.;
format latestdt yymmddd10.;
datalines;
1 2020-06-17
2 2020-07-19
3 2020-10-21
4 2020-10-26
5 2020-11-05
6 2020-11-13
7 2020-11-13
;
run;
data want;
set have;
interval=dif(latestdt);
if not interval then interval=0;
run;
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