I need help with assigning a new id (proposed id).I'm trying to get the final data below based on the fact that
If Admn_no have same sch_ID and name, or sch_ID and Birth_Day or name and Birth_day, assign the same the same proposed ID throughout.
The assumption is they are the same people. If that criterion is not met, then give it a new proposed id since the person is likely a new person.
SAMPLE data
Adm_no Sch_ID NAME Birth_Day
1 6116 CALVIN 03/10/1970
2 6176 CALVIN 03/10/1970
3 6176 CALVIN 10/03/1970
4 0176 CALVIN 03/10/1970
5 6176 10/03/1970
6 6176 MALVIN 03/10/1970
7 6176 03/10/1970
8 CALVIN 03/10/1970
9 6116 03/10/1970
10 12345 JOHN 01/02/1978
11 6543 TOM 03/06/1977
12 2348 CALVIN
Final
Adm_no Sch_ID NAME Birth_Day Proposed_id
1 6116 CALVIN 03/10/1970 1
2 6176 CALVIN 03/10/1970 1
3 6176 CALVIN 10/03/1970 1
4 0176 CALVIN 03/10/1970 1
5 6176 10/03/1970 1
6 6176 MALVIN 03/10/1970 1
7 6176 03/10/1970 1
8 CALVIN 03/10/1970 1
9 6116 03/10/1970 1
10 12345 JOHN 01/02/1978 2
11 6543 TOM 03/06/1977 3
12 2348 CALVIN 4
Since the odds of two students having the same birthdate in a class is extremely high (see, e.g., Math Guy: The Birthday Problem : NPR ), using that criterion at the school level doesn't appear to be a good way to go.
If you are only trying to find transposition errors, then I would use one of the similarity functions like spedis (SAS(R) 9.2 Language Reference: Dictionary, Fourth Edition ) on all three variables and determine your criterion based on the values you get, but using all three variables in a single combination.
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.