Adding rows to a table

[Caetreviop543]

Hi,

I am trying to add 16 rows to a table, where variable x1 goes from 1 to 5 by .25 increments. x2 is the square of x1, and the remaining variables are the same (either 0 or the mean).

For example,

ID            x1 x2 x3 x4 x5 x6 x7

.               .   .   .    .   .   .    .

.               .   .   .    .   .   .    .

.               .   .   .    .   .   .    .

Dum1      1  1  0   0  0  0  27.9

Dum125 1.25 1.56 0 0 0 0 27.9

Dum150 1.50 2.25 0 0 0 0 27.9

Dum175 1.75 3.06 0 0 0 0 27.9

...

I originally used the input statement to create the data (above), and then appended it my original dataset. Does anyone know a better way?

Thanks in advance,

Emily

[ballardw · Accepted solution]

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@Caetreviop543 wrote:

Hi,

I am trying to add 16 rows to a table, where variable x1 goes from 1 to 5 by .25 increments. x2 is the square of x1, and the remaining variables are the same (either 0 or the mean).

For example,

ID            x1 x2 x3 x4 x5 x6 x7

.               .   .   .    .   .   .    .

.               .   .   .    .   .   .    .

.               .   .   .    .   .   .    .

Dum1      1  1  0   0  0  0  27.9

Dum125 1.25 1.56 0 0 0 0 27.9

Dum150 1.50 2.25 0 0 0 0 27.9

Dum175 1.75 3.06 0 0 0 0 27.9

...

I originally used the input statement to create the data (above), and then appended it my original dataset. Does anyone know a better way?

Thanks in advance,

Emily

---

How do we know when the other variables are 0 or the mean? Mean of what?

And where does the 27.9 for x7 come from?

I would start with something like:

data want;
   length id $ 10.;
   do x1=1 to 5 by .25;
      id = cats('Dum',x1*100);
      x2= x1*x1;
      x3=0;
      x4=0;
      x5=0;
      x6=0;
      x7=27.9;
      output;
   end;
run;

If this needs to be at the end of another data set then something like:

data final;
   set have
       want;
end;

Or use Proc Append but that requires all the variables in the "want" set to already exist in the have data set.

[Caetreviop543]

Great! That works. I just meant that x3-x7 are either binary or continuous, where binary variables are set to 0 and continuous variables (x7) are set to the mean. Basically, I’m setting all my covariates to the same value. 27.9 corresponds to the mean age for my sample.

Is it possible to create another variable (x0) with the same values as x1? Ideally the data would look like this:

ID              x0  x1 x2 x3 x4 x5 x6 x7 x8

DUM100    1  1  1  1  0  0  0  0  27.9

DUM125    1.25  1.25  1.56  1.56  0  0  0  0  27.9

DUM150    1.50  1.50  2.25  2.25  0  0  0  0  27.9

However, the code below groups x1 by x0, resulting in:

ID              x0  x1 x2 x3 x4 x5 x6 x7

DUM100    1  1  1  1  0  0  0  27.9

DUM125    1  1.25  1  1.56  0  0  0  0  27.9

DUM150    1  1.50  1  2.25  0  0  0  0  27.9

data want;

   length id $ 10.;

   do x0=1 to 5 by .25;

   do x1=1 to 5 by .25;

      id = cats('Dum',x1*100);

      x2=x0*x0;

      x3=x1*x1;

      x4=0;

      x5=0;

      x6=0;

      x7=0;

      x8=27.9;

      output;

   end;

   end;

run;

Thanks for your help!

[ChrisNZ]

> Does anyone know a better way?

If the base table already exists, creating a small table and appending it is the best way.

Otherwise you recreate the whole table just to add a few rows.

[Caetreviop543]

Ok, that makes sense. I figured it was the best way, just wanted to make sure.