BookmarkSubscribeRSS Feed
need_sas_help
Calcite | Level 5


I have the following dataset with following variables:
ID (Character) test (character) date (character) result (numeric)


ID            test      date                  result
101          run     15JUL1978         1
101          run     18JUL1976         1
101          run     17JUL1978         2
101          run     20JUL1976         4
101          case   15OCT2014       5
101          case   17NOV2016       4
101          case   15DEC2017        .
102          rub      28MAR2017      7
102          rub      29MAR              8
102          rub      APR2017           5

 

need retian statement used or proc sql to create a new variable "MAXRESULT" to
retain the maxmimum vaue from the presvois itration and compare with the present one
and keep the maximum one and


NEED A RESULT Datset LIKE AS BELOW. Also need to pay attention to the incomplete date
and missing result.

 

ID    test   date                      result    MAXRESULT
101  run   15JUL1978             1                 1
101  run    17JUL1978            2                 2
101  run    18JUL1976            1                 2
101  run    20JUL1976            4                 4
101  case  15OCT2014           5                5
101  case  17NOV2016           4                 5
101  case  15DEC2017            .                 5
102  rub    28MAR2017           7                 7
102  rub    29MAR                   8                 8 (Incomplete Date)
102  rub    APR2017                5                 8 (Incomplete Date)

Thank you so much from the bottom of my heart.

5 REPLIES 5
art297
Opal | Level 21

How do you want to treat incomplete dates? Delete them? Assign a day (e.g. 1 15 or end of month) if missing day? What about for missing year?

 

Art, CEO, AnalystFinder.com

 

MINX
Obsidian | Level 7

Retain statement works for me. 

data want;
	set have;
	retain MAXRESULT;
	if _n_ = 1 then MAXRESULT=result;
	if result > MAXRESULT then MAXRESULT = result;
run;
novinosrin
Tourmaline | Level 20
data have;
input  (ID            test      date) (:$10.)                  result;
datalines;
101          run     15JUL1978         1
101          run     18JUL1976         1 
101          run     17JUL1978         2
101          run     20JUL1976         4
101          case   15OCT2014       5
101          case   17NOV2016       4
101          case   15DEC2017        .
102          rub      28MAR2017      7
102          rub      29MAR              8
102          rub      APR2017           5
;

data want;
set have;  
by id;
retain 	max_result;
if first.id then call missing(max_result);
max_result=max(max_result,result);
run;
need_sas_help
Calcite | Level 5
Sorry, Actually my typing had some errors  and the new problem should as  below (there is some changes), can you please check it:

I have the following dataset with following variables:
ID (Character) test (character) date (character) result (numeric)


ID       test   date               result
101      run    15JUL1978           1
101      run    15JUL1978           2
101      run    15JUL1978           1
101      run    18JUL1976           1 
101      run    18JUL1976           1 
101      run    18JUL1976           1 
101      case   15OCT2014         5
101      case   15OCT2014         5
101      case   15DEC2017          .
102      rub     28MAR2017         7
102      rub     28MAR2017         6          
102      rub     29MAR                8
102      rub     APR2017             5

need retian statement used or proc sql to create a new variable "MAXRESULT" to 
retain the maxmimum value (by ID test  date(  meaning per time point) from the presvois itration and compare with the present one
and keep the maximum one and
NEED A RESULT Datset LIKE AS BELOW. Also need to pay attention to the incomplete date 
and missing result. 


ID       test   date               result    MAXRESULT
101      run    15JUL1978           1          1
101      run    15JUL1978           2          2
101      run    15JUL1978           1          2 
101      run    18JUL1976           1          1
101      run    18JUL1976           1          1 
101      run    18JUL1976           1          1
101      case   15OCT2014          5          5 
101      case   15OCT2014          5          5
101      case   15DEC2017           .          .
102      rub     28MAR2017         7           7 
102      rub     28MAR2017         6           7
102      rub     29MAR                8           8
102      rub     APR2017             5           5      


Thank you so much from the bottom of my heart.
novinosrin
Tourmaline | Level 20
data have;
input  (ID            test      date) (:$10.)                  result;
datalines;
101      run    15JUL1978           1
101      run    15JUL1978           2
101      run    15JUL1978           1
101      run    18JUL1976           1 
101      run    18JUL1976           1 
101      run    18JUL1976           1 
101      case   15OCT2014         5
101      case   15OCT2014         5
101      case   15DEC2017          .
102      rub     28MAR2017         7
102      rub     28MAR2017         6          
102      rub     29MAR                8
102      rub     APR2017             5
;

data want;
set have;  
by id date notsorted;
retain 	max_result;
if first.date then call missing(max_result);
max_result=ifn(missing(result), ., max(max_result,result));
run;

Ready to join fellow brilliant minds for the SAS Hackathon?

Build your skills. Make connections. Enjoy creative freedom. Maybe change the world. Registration is now open through August 30th. Visit the SAS Hackathon homepage.

Register today!
How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 5 replies
  • 1678 views
  • 0 likes
  • 4 in conversation