"data voter;
input Age Party : $1. (Ques1-Ques4) ($1. +1);
datalines;
23 D 1 1 2 2
45 R 5 5 4 1
67 D 2 4 3 3
39 R 4 4 4 4
19 D 2 1 2 1
75 D 3 3 2 3
57 R 4 3 4 4
;"
Above is a part of code I quoted. What I cannot understand is the "+1" following "$1." in second line.
What is its function? If without it, what will be wrong?
Party : $1.
Means to eat a character, colon means to stop read when encounter a delimiter blank ,
Because it is list input method, so point will move a unit forward.
(Ques1-Ques4) ($1. +1);
is equal to Ques1 $1. +1 Ques2 $1. +1 Ques3 $1. +1 Ques4 $1. +1
Ksharp
The way it is written, yes, it is needed. Conversely, something like the following would also work:
data voter;
informat party ques1-ques4 $1.;
input Age Party Ques1-Ques4;
datalines;
23 D 1 1 2 2
45 R 5 5 4 1
67 D 2 4 3 3
39 R 4 4 4 4
19 D 2 1 2 1
75 D 3 3 2 3
57 R 4 3 4 4
;
You have a number of options and capabilities when it comes to inputting data in SAS. For a nice overview, take a look at:
http://support.sas.com/documentation/cdl/en/lrcon/62955/HTML/default/viewer.htm#a003209907.htm
Party : $1.
Means to eat a character, colon means to stop read when encounter a delimiter blank ,
Because it is list input method, so point will move a unit forward.
(Ques1-Ques4) ($1. +1);
is equal to Ques1 $1. +1 Ques2 $1. +1 Ques3 $1. +1 Ques4 $1. +1
Ksharp
I have one ques..
If I am not giving +1, then it is not taking any values for Ques2 and Ques4, By Default how it is working..plz explain?
Narenda,
Without the +1, the blanks between the numbers are read as data. If you look carefully, you would see that the value for Ques3 is actually the value that was meant for Ques2 in the original.
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