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robertrao
Quartz | Level 8

HI Team,

i was trying to use an if condition like the following and I get a syntax error.

could you please help me correct this?????

DAta want want2;

set have;

If datepart(time) between "begin" and "end " then output want;

if datepart(time) between "begin2 " and "end2" theN output want2;

run;

THanks

1 ACCEPTED SOLUTION

Accepted Solutions
Tom
Super User Tom
Super User

Two problems

1)  The IF statement does not support that SQL specific BETWEEN operator even though the WHERE statement does.

Use the normal SAS syntax :

  "&begin"d <= datepart(time) <= "&end"d

Or the expanded syntax :

  "&begin"d <= datepart(time) and datepart(time) <= "&end"d


2) You cannot compare a numeric (dates are numbers of days since 1/1/1960) with a character string. If you format the values in DATE format then you can use date literals.

%let begin=01JAN2013;

%let end=31MAR2013;

%let begin2=01APR2013;

%let end2=30JUN2013;

data want want2;

  set have;

  if "&begin"d <= datepart(time) <= "&end"d then output want;

  if "&begin2"d <= datepart(time) <= "&end2"d then output want2;

run;

View solution in original post

2 REPLIES 2
Tom
Super User Tom
Super User

Two problems

1)  The IF statement does not support that SQL specific BETWEEN operator even though the WHERE statement does.

Use the normal SAS syntax :

  "&begin"d <= datepart(time) <= "&end"d

Or the expanded syntax :

  "&begin"d <= datepart(time) and datepart(time) <= "&end"d


2) You cannot compare a numeric (dates are numbers of days since 1/1/1960) with a character string. If you format the values in DATE format then you can use date literals.

%let begin=01JAN2013;

%let end=31MAR2013;

%let begin2=01APR2013;

%let end2=30JUN2013;

data want want2;

  set have;

  if "&begin"d <= datepart(time) <= "&end"d then output want;

  if "&begin2"d <= datepart(time) <= "&end2"d then output want2;

run;

robertrao
Quartz | Level 8

Thank you very much Tom. That was very helpful.

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