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jcapua2
Fluorite | Level 6

Hello,

 

I have a dataset filled with character variables.

 

data have;

patientinfection_1infection_2infection_3
abcvirus  
xyzfungusvirus 
lmnbacteriafungusvirus

 

I want to produce one frequency table to find all occurrences in the variable:

 any infection
virus3
fungus2
bacteria1

 

Is there a shorter way in SAS to do this? Thank you!

2 REPLIES 2
novinosrin
Tourmaline | Level 20
data have;
input (patient	infection_1	infection_2	infection_3) (:$10.);
cards;
abc	virus	. . 	 
xyz	fungus	virus	. 
lmn	bacteria	fungus	virus
;

proc transpose data=have out=_have(keep=col1 where=(col1 ne ' ' ));
by patient notsorted;
var infection:;
run;

proc freq data=_have noprint;
tables col1/out=want(keep=col1 count);
run;
mkeintz
PROC Star
data need (keep=infection) / view=need;
  set have  ;
  array inf {*} infection_: ;
  length infection $12;
  do I=1 to dim(inf) while (inf{I}^=' ');
    infection=inf{I};
    output;
  end;
run;

proc freq data=need;
  tables infection;
run;

 

This program assumes that if a row has fewer than 3 infections, the non-blank values are the leftmost.

--------------------------
The hash OUTPUT method will overwrite a SAS data set, but not append. That can be costly. Consider voting for Add a HASH object method which would append a hash object to an existing SAS data set

Would enabling PROC SORT to simultaneously output multiple datasets be useful? Then vote for
Allow PROC SORT to output multiple datasets

--------------------------

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