Hi
how can I convert this text to a date I can use in SAS.?
April 1, 2016
currently stored as CHAR $18
thanks
data want;
set have;
Sasdate = input(textdate, anydtdte32.);
format Sasdate mmddyy10.;
run;
Typically:
sas_date = input(string_date, worddate18.);
Then apply a format to SAS_DATE such as:
format sas_date yymmdd10.;
or
format sas_date date9.;
Thanks for the response but im getting the following error...
sas_date = input(date, worddate18.);
-----------
48
ERROR 48-59: The informat WORDDATE was not found or could not be loaded
Usually there's an informat for the date, but this doesn't have an informat that I could find.
You can create it into a date format that SAS will recognize, I used Date9. format, since it's the most common in SAS.
I use the SUBSTR, SCANx2 function to extract the month, day and year, respectively, and the CATT to concatenate them together.
data have;
informat date_char $20.;
input date_char $20.;
cards;
April 1, 2016
December 24, 2016
April 30, 2015
May 18, 2014
November 1, 2012
February 28, 2016
;
run;
data want;
set have;
date_format9 = catt(put(input(scan(date_char, 2), 2.), z2.),
substr(date_char, 1, 3),
scan(date_char, 3)
);
date_num = input(date_format9, date9.);
format date_num date9.;
run;
You guys are right! There's a WORDDATE18 format, but not a WORDDATE18 informat.
Reeza's idea looks good. I might simplify one part:
date_format9 = cats( scan(date_char, 2, ' ,'), substr(date_char, 1, 3), scan(date_char, 3) );
Note that both blanks and commas are being used as delimiters in the first SCAN function.
data want;
set have;
Sasdate = input(textdate, anydtdte32.);
format Sasdate mmddyy10.;
run;
@ballardw Interesting. I tried with ANYDTDTE but didn't specify a width, and that didn't work. I forgot there's a default width 🙂
Hi there,
Is there a similar solution to extract the time from this text var format $25.
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