Dear All,
I would like to learn how to calculate % change, when two strings are compared.
Here is the original file:
1 | RAT | CAT |
---|---|---|
2 | BELL | BALL |
3 | TIME | TOM |
As there is only one character that is different in the first observation, it should return 1/3 %(number of deviation / total number of char in the original).
Desired output is something like this:
1 | RAT | CAT | 33 |
---|---|---|---|
2 | BELL | BALL | 25 |
3 | TIME | TOM | 50 |
Thanks in advance,
Jijil Ramakrishnan
Try this for the desired output.
data have;
input obs var1 $ var2 $;
datalines;
1 RAT CAT
2 BELL BALL
3 TIME TOM
;
data want;
set have;
do i=1 by 1 while(substr(var1,i,1) ne ' ');
if index(var2,substr(var1,i,1))>0 then cnt+1;
output;
end;
cnt=0;
run;
data final (drop=i cnt);
set want;
by obs;
if last.obs;
diff=(i-cnt)/i*100;
format diff 8.0;
run;
Thank you so much.
Approximate matches between strings is an already well researched topic. SAS provides you with many tools in that area. Please look at SAS functions COMPGED, COMPLEV, SOUNDEX, and SPEDIS.
PG
Thanks a lot!
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