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anweinbe
Quartz | Level 8

Good afternoon,

 

I have a column within my dataset called "file_accepted". A sample record shows as "09MAR2007:16:12:21". 

 

I am trying to create a field that grabs the 2 digits after the first colon, in this example the 16... which is military time for 4pm. Ideally, I would like my new field to be coded as "1" if the time is at 4PM or after, and "0" if the time is before 4PM. 

 

Thank you!

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

What type of variable, character or numeric? If the variable is a SAS datetime value, numeric with a format of DATETIME18 or similar then you can check the Hour of the value with the hour function:

 

data want;

   set have;

   newvar = (Hour(file_accepted) ge 16);

run;

 

If it isn't a datetime value then you really should make a datetime valued version as most of the steps involving comparisons, selections or other manipulations of datetimes start with that conversion.

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3 REPLIES 3
ballardw
Super User

What type of variable, character or numeric? If the variable is a SAS datetime value, numeric with a format of DATETIME18 or similar then you can check the Hour of the value with the hour function:

 

data want;

   set have;

   newvar = (Hour(file_accepted) ge 16);

run;

 

If it isn't a datetime value then you really should make a datetime valued version as most of the steps involving comparisons, selections or other manipulations of datetimes start with that conversion.

anweinbe
Quartz | Level 8
That did it! Thank you!!!
Reeza
Super User
What's your data type and format on that column?

If it's a datetime you can likely use the HOUR() function.

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